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If the lines 4x + 3y = 84 and 3x + ky + 7 = 0 are perpendicular to each other. Then the value of k is ______.

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Question

If the lines 4x + 3y = 84 and 3x + ky + 7 = 0 are perpendicular to each other. Then the value of k is ______.

Options

  • 4

  • −4

  • `1/4`

  • `-1/4`

MCQ
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Solution

If the lines 4x + 3y = 84 and 3x + ky + 7 = 0 are perpendicular to each other. Then the value of k is −4.

Explanation:

Given,

1st equation:

⇒ 4x + 3y = 84

⇒ 3y = −4x + 84

⇒ y = `−4/3x + 84/3`

⇒ y = `−4/3x + 28`

Comparing above equation with y = mx + c, we get:

Slope of first equation = `−4/3`

2nd equation:

⇒ 3x + ky + 7 = 0

⇒ ky = −3x − 7

⇒ y = `−3/kx − 7/k`

Slope of second equation = `−3/k`

We know that,

Product of slope of two perpendicular lines = −1

⇒ `−4/3×−3/k = −1`

⇒ `4/k = −1`

⇒ −k = 4

⇒ k = −4

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Chapter 14: Equation of a Line - TEST YOURSELF [Page 201]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 14 Equation of a Line
TEST YOURSELF | Q 1. (e) | Page 201
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