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If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is rijkr→.(5i^-3j^-2k^) = 38. - Mathematics

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Question

If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is `vec"r".(5hat"i" - 3hat"j" - 2hat"k")` = 38.

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  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:

The given equation of the plane is `vec"r".(5hat"i" - 3hat"j" - 2hat"k")` = 38

If the foot of the perpendicular to this plane is (5, – 3, – 2)

i.e., `5hat"i" - 3hat"j" - 2hat"k"` then

`(5hat"i" - 3hat"j" - 2hat"k").(5hat"i" - 3hat"j" - 2hat"k")` = 38

⇒ 25 + 9 + 4 = 38

38 = 38 .....(satisfied)

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Chapter 11: Three Dimensional Geometry - Exercise [Page 240]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 11 Three Dimensional Geometry
Exercise | Q 49 | Page 240

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