हिंदी

If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is rijkr→.(5i^-3j^-2k^) = 38.

Advertisements
Advertisements

प्रश्न

If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is `vec"r".(5hat"i" - 3hat"j" - 2hat"k")` = 38.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य
Advertisements

उत्तर

This statement is True.

Explanation:

The given equation of the plane is `vec"r".(5hat"i" - 3hat"j" - 2hat"k")` = 38

If the foot of the perpendicular to this plane is (5, – 3, – 2)

i.e., `5hat"i" - 3hat"j" - 2hat"k"` then

`(5hat"i" - 3hat"j" - 2hat"k").(5hat"i" - 3hat"j" - 2hat"k")` = 38

⇒ 25 + 9 + 4 = 38

38 = 38 .....(satisfied)

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Three Dimensional Geometry - Exercise [पृष्ठ २४०]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 11 Three Dimensional Geometry
Exercise | Q 49 | पृष्ठ २४०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×