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If θθθθtan2θ+tanθ1-tanθtan2θ = 0, then the general value of θ is ______.

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Question

If `(tan2θ + tanθ)/(1 - tanθtan2θ)` = 0, then the general value of θ is ______.

Options

  • nπ; n ∈ I

  • `(nπ)/3;n∈I`

  • `(nπ)/4;n∈I`

  • `(nπ)/6;n∈I`

MCQ
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Solution

If `(tan2θ + tanθ)/(1 - tanθtan2θ)` = 0, then the general value of θ is `underlinebb((nπ)/3;n∈I)`.

Explanation:

`(tan2θ + tanθ)/(1 - tanθtan2θ)` = 0

⇒ tan(3θ) = 0

⇒ 3θ = nπ

⇒ θ = `(nπ)/3, n∈I`

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Trigonometric Equations
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