Question

If `(tan2θ + tanθ)/(1 - tanθtan2θ)` = 0, then the general value of θ is ______.

विकल्प

• nπ; n ∈ I

• `(nπ)/3;n∈I`

• `(nπ)/4;n∈I`

• `(nπ)/6;n∈I`

Answer 1

If `(tan2θ + tanθ)/(1 - tanθtan2θ)` = 0, then the general value of θ is `underlinebb((nπ)/3;n∈I)`.

Explanation:

`(tan2θ + tanθ)/(1 - tanθtan2θ)` = 0

⇒ tan(3θ) = 0

⇒ 3θ = nπ

⇒ θ = `(nπ)/3, n∈I`