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Question
If `tan θ = a/b` then `((cos θ + sin θ))/((cos θ - sin θ))` = ?
Options
`(a + b)/(a - b)`
`(a - b)/(a + b)`
`(b + a)/(b - a)`
`(b - a)/(b + a)`
MCQ
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Solution
`bb((b + a)/(b - a))`
Explanation:
Dividing num. and denom. by cos θ, we get
`((cos θ + sin θ))/((cos θ - sin θ)) = ((1 + tan θ))/((1 - tan θ))`
= `((1 + a/b))/((1 - a/b))`
= `((b + a))/((b - a))`
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