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If tan^245° – cos^230° = x sin 45° cos 45° then x = ?

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Question

If tan245° – cos230° = x sin 45° cos 45° then x = ?

Options

  • 2

  • –2

  • `1/2`

  • `-1/2`

MCQ
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Solution

`bb(1/2)`

Explanation:

`x = (tan^2 45^circ - cos^2 30^circ)/(sin 45^circ cos 45^circ)`

= `(1 - (sqrt(3)/2)^2)/((1/sqrt(2) xx 1/sqrt(2)))`

= `((1 - 3/4))/((1/2))`

= `(1/4 xx 2/1)`

= `1/2`

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Chapter 11: T-Ratios of Some Particular Angles - MULTIPLE-CHOICE QUESTIONS (MCQ) [Page 576]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 11 T-Ratios of Some Particular Angles
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 6. | Page 576
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