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Question
If tan 2θ = cot (θ + 6º), where 2θ and (θ + 6º) are acute angles, find the value of θ.
Sum
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Solution
We have,
tan 2θ = cot (θ + 6º)
⇒ cot(90º – 2θ) = cot (θ + 6º)
⇒ 90º – 2θ = θ + 6º ⇒ 3θ = 84º
⇒ θ = 28º
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