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Question
If `sin θ = 1/sqrt(11)`, then cot θ equals
Options
`sqrt(11)/sqrt(10)`
`sqrt(10)/sqrt(11)`
`sqrt(10)`
`sqrt(11)`
MCQ
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Solution
`bb(sqrt(10))`
Explanation:
1. Identify the given value
The sine of an angle θ is defined in a right triangle as the ratio of the perpendicular (p) to the hypotenuse (h).
`sin θ = p/h`
= `1/sqrt(11)`
From this, we can let:
p = 1
`h = sqrt(11)`
2. Find the adjacent side (base)
Using the Pythagorean theorem (h2 = p2 + b2), where b is the base:
`(sqrt(11))^2 = 1^2 + b^2`
11 = 1 + b2
b2 = 10
`b = sqrt(10)`
3. Calculate cotangent
The cotangent of an angle is the ratio of the base (b) to the perpendicular (p).
`cot θ = b/p`
`cot θ = sqrt(10)/1`
= `sqrt(10)`
Depending on which quadrant θ lies in, the value can be positive or negative. Since no quadrant is specified, the general solution is `± sqrt(10)`.
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