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Question
If r.v. X assumes values 1, 2, 3, ..., n with equal probabilities then E(X) = `(n + 1)/(2)`.
Options
True
False
MCQ
True or False
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Solution
This statement is True.
Explanation:
| X | 1 | 2 | 3 | .... | n |
| P(X) | `1/n` | `1/n` | `1/n` | `1/n` |
E(X) = `sum x_i * P(x_i)`
= `1(1/n) + 2(1/n) + 3(1/n) + .... + n(1/n)`
= `(1)/n (1 + 2 + 3 + .... + n)`
= `(1)/n * (n(n + 1))/(2)`
= `(n + 1)/(2)`
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