Question

If the roots of x² + kx + k = 0 are real and equal, what is the value of k?

Options

•  0

• 4

• 0 or 4

•  2

Answer 1

0 or 4

X^2+kx+k has distinct real solution .

So, for distinct real solution

Use formula b^2 - 4ac>0

a = 1 , b= k , c = k

Put formula b^2– 4ac>0

K^2 - 4×1×k >0

K^2 - 4k>0

K(k-4)>0

K>0, k -4>0

K>0, k<4