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Question
If p(x) = x2 – 4x + 3, then evaluate : `p(2) - p(–1) + p(1/2)`
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Solution
Given, p(x) = x2 – 4x + 3
Now, p(2) = (2)2 – 4 × 2 + 3
= 4 – 8 + 3
= –1
p(–1) = (–1)2 – 4(–1) + 3
= 1 + 4 + 3
= 8
And `p(1/2) = (1/2)^2 - 4 xx 1/2 + 3`
= `1/4 - 2 + 3`
= `(1 - 8 + 12)/4`
= `5/4`
∴ `p(2) - p(-1) + p(1/2) = -1 - 8 + 5/4`
= `-9 + 5/4`
= `(-36 + 5)/4`
= `(-31)/4`
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