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If $$p(x) = x^2 - 2\sqrt{2}x + 1$$, $$p(2\sqrt{2}) = ?$$

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Question

If $$p(x) = x^2 - 2\sqrt{2}x + 1$$, $$p(2\sqrt{2}) = ?$$

Options

  • 0

  • 1

  • –1

  • –8

MCQ
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Solution

1

Explanation:

$$p(2\sqrt{2}) = (2\sqrt{2})^2 - 2\sqrt{2}(2\sqrt{2}) + 1$$

$$= 8 - 8 + 1$$

$$= 1$$

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Chapter 8: Remainder Theorem and Factor Theorem - COMPETENCY-FOCUSED QUESTIONS [Page 128]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 8 Remainder Theorem and Factor Theorem
COMPETENCY-FOCUSED QUESTIONS | Q 3. | Page 128
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