Question

If $$p(t) = t^2 - t - 2$$, then the value of $$p\left(-\frac{1}{3}\right)$$ is ______.

Options

• $$-2$$

• $$-\frac{10}{9}$$

• $$-\frac{14}{9}$$

• 0

Answer 1

If $$p(t) = t^2 - t - 2$$, then the value of $$p\left(-\frac{1}{3}\right)$$ is `underlinebb(-14/9)`.

Explanation:

$$p\left(-\frac{1}{3}\right)=\frac{1}{9} + \frac{1}{3} - 2 = -\frac{14}{9}$$.