Question

If P(E) = 0.05, then P(not E) =

Options

• −0.05

• 0.5

• 0.9

•  0.95

Answer 1

`P(E)=0.05`

TO FIND:` P(overline E)`

We know that sum of probability of occurrence of an event and probability of non occurrence of an event is 1. Therefore 

`P(overline E)=1`

`0.05+p(overlineE)=1`

        `  p(overlineE)=1-0.05`

           `P(overlineE)=0.95`