Question

If n electrons of charge e⁻, flow a circuit in t seconds, then the current I in amperes is:

Options

• \[\text{I} = \frac{n e^{-}}{t}\]

• \[\text{I} = \frac{t}{n e^{-}}\]

• I = n e⁻ × t

• I = n e⁻ + t

Answer 1

\[\text{I} = \frac{n e^{-}}{t}\]

Explanation:

The total charge carried by n electrons is Q = n e⁻

Since $$I = \frac{Q}{t}$$ we get $$I = \frac{ne^{-}}{t}$$.