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If N = 98 + 99 + 910 + 911, then how many positive factors of N are there?

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Question

If N = 98 + 99 + 910 + 911, then how many positive factors of N are there?

Options

  • 102

  • 108

  • 204

  • 128

MCQ
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Solution

204

Explanation:

N = 98 + 99 + 910 + 911

N = 98 (1 + 9 + 92 + 93)

N = 98 × 820

N = 316 × 22 × 51 × 411

∴ Divisor = (16 + 1) (2 + 1) (1 + 1) (1 + 1) = 204

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Number System (Entrance Exam)
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