Advertisements
Advertisements
Question
If MR = 20 – 5x + 3x2, Find total revenue function
Advertisements
Solution
MR = 20 – 5x + 3x2
Total Revenue function
R = `int ("MR") "d"x`
= `int (20 - 5x + x^2) "d"x`
R = `20x = (5x^2)/2 + (3x^3)/3 + "k"`
When x = 0
R = 0
⇒ k = 0
∴ R = `20x - 5/2x^2 + x^3`
APPEARS IN
RELATED QUESTIONS
The cost of an overhaul of an engine is ₹ 10,000 The operating cost per hour is at the rate of 2x – 240 where the engine has run x km. Find out the total cost if the engine runs for 300 hours after overhaul
Elasticity of a function `("E"y)/("E"x)` is given by `("E"y)/("E"x) = (-7x)/((1 - 2x)(2 + 3x))`. Find the function when x = 2, y = `3/8`
The elasticity of demand with respect to price for a commodity is given by `((4 - x))/x`, where p is the price when demand is x. Find the demand function when the price is 4 and the demand is 2. Also, find the revenue function
If the marginal revenue function for a commodity is MR = 9 – 4x2. Find the demand function.
Find the revenue function and the demand function if the marginal revenue for x units is MR = 10 + 3x – x2
If the supply function for a product is p = 3x + 5x2. Find the producer’s surplus when x = 4
Choose the correct alternative:
If the marginal revenue MR = 35 + 7x – 3x2, then the average revenue AR is
Choose the correct alternative:
For a demand function p, if `int "dp"/"p" = "k" int ("d"x)/x` then k is equal to
The marginal revenue function for a firm given by MR = `2/(x + 3) - (2x)/(x + 3)^2 + 5`. Show that the demand function is P = `(2x)/(x + 3)^2 + 5`
The price elasticity of demand for a commodity is `"p"/x^3`. Find the demand function if the quantity of demand is 3 when the price is ₹ 2.
