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Question
If log5 a = 2, log3 b = 3, find the value of 3a – 2b.
Sum
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Solution
Given log5 a = 2
a = 52
a = 25
⇒ log3 b = 3
b = 33
b = 27
Substitute the values:
3a – 2b
= 3 × 25 – 2 × 27
= 75 – 54
= 21
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