Question

If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 1.2

Answer 1

log 2 = 0.3010 and log 3 = 0.4771
log 1.2
= log`12/10`
= log 12 - log 10            ...[ loga`m/n` = log_am - log_an ]
= log 2 x 2 x 3 - 1           ...[ ∵ log 10 = 1 ]
= log 2 x 2 + log 3 - 1    ...[ log_amn = log_am + log_an ]
= log 22 + log 3 - 1
= 2log2 + log3 - 1          ...[ nlogam = logamn ]
= 2( 0.3010 ) + 0.4771 - 1  ...[ ∵ log 2 = 0.3010 and log3 = 0.4771 ] 
= 1.0791 - 1
= 0.0791