Question

If k + 2, 4k – 6 and 3k – 2 are three consecutive terms of an A.P., then the value of k is ______.

Options

• 3

• –3

• 4

• –4

Answer 1

If k + 2, 4k – 6 and 3k – 2 are three consecutive terms of an A.P., then the value of k is 3.

Explanation:

Given k + 2, 4k – 6 and 3k – 2 are three consecutive terms of an A.P.

Then (4k – 6) – (k + 2) = (3k – 2) – (4k – 6)

3k – 8 = – k + 4

4k = 8 + 4 = 12

k = `12/4` = 3