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If H J is the heat absorbed by a substance such that θ°C is the rise in its temperature then the thermal capacity of the substance is:

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Question

If H J is the heat absorbed by a substance such that θ°C is the rise in its temperature then the thermal capacity of the substance is:

Options

  • H θ J °C

  • \[\frac{H}{\theta} \frac{\mathrm{~J}}{{ }^{\circ} \mathrm{C}}\]

  • \[\frac{\theta}{H} \frac{{ }^{\circ} \mathrm{C}}{\mathrm{J}}\]

  • none of these

MCQ
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Solution

\[\frac{H}{\theta} \frac{\mathrm{~J}}{{ }^{\circ} \mathrm{C}}\]

Explanation:

Thermal capacity is the heat required for a 1°C rise in temperature.

So $$C' = \frac{H}{\theta}$$, with unit J/°C.

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Chapter 10: Calorimetry - EXERCISE-1 [Page 235]

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Goyal Brothers Prakashan A New Approach to ICSE Physics [English] Class 10
Chapter 10 Calorimetry
EXERCISE-1 | Q 16. | Page 235
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