Question

If figure OPRQ is a square and ∠MLN = 90°. Prove that ∆LOP ~ ∆QMO

Answer 1

In ∆LOP and ∆QMO

∠OLP = ∠OQM = 90°

∠LOP = ∠OMQ  ...(Since OQRP is a square OP || MN)

∴ ∆LOP~ ∆QMO  ...(By AA similarity)