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If (cot θ – 1)/(cot θ + 1) = (1 – sqrt(3))/(1 + sqrt(3)) then find the acute angle θ.

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Question

If `(cot θ - 1)/(cot θ + 1) = (1 - sqrt(3))/(1 + sqrt(3))` then find the acute angle θ.

Sum
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Solution

`(1 + sqrt(3))(cot θ - 1) = (1 - sqrt(3))(cot θ + 1)`

⇒ `{(1 + sqrt(3)) - (1 - sqrt(3))} cot θ = (1 - sqrt(3)) + (1 + sqrt(3))`

⇒ `2sqrt(3) cot θ = 2`

⇒ `cot θ = 1/sqrt(3)`

⇒ cot θ = cot 60°

⇒ θ = 60°

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Chapter 11: T-Ratios of Some Particular Angles - EXERCISE 11 [Page 573]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 11 T-Ratios of Some Particular Angles
EXERCISE 11 | Q 22. | Page 573
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