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If a and B Are Coefficients of Xn in the Expansions of ( 1 + X ) 2 N and ( 1 + X ) 2 N − 1 Respectively, Then Write the Relation Between a and B. - Mathematics

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Question

If a and b are coefficients of xn in the expansions of \[\left( 1 + x \right)^{2n} \text{ and } \left( 1 + x \right)^{2n - 1}\] respectively, then write the relation between a and b.

 
 
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Solution

\[\text{ Coefficient of } x^n \text{ in the expansion}  (1 + x )^{2n} =^{2n}{}{C}_n = a\]

\[\text{ Coefficient of } x^n \text{ in the expansion}  (1 + x )^{2n - 1} = ^{2n - 1}{}{C}_n = b\]

\[\text{ Now, we have:}  \]

\[ ^{2n}{}{C}_n = \frac{2n!}{n! . n!} = \frac{2n(2n - 1)!}{n\left( n - 1 \right)! n!} . . . \left( 1 \right)\]

\[ \text{ and }  ^{2n - 1}{}{C}_n = \frac{(2n - 1)!}{n!(n - 1)!} . . . \left( 2 \right)\]

\[\text{ Dividing equation }  \left( 1 \right) \text{ by }  \left( 2 \right), \text{ we get } \]

\[ \Rightarrow \frac{^{2n}{}{C}_n}{^{2n - 1}{}{C}_n} = \frac{2n(2n - 1)! n! (n - 1)!}{n\left( n - 1 \right)! n! (2n - 1)!}\]

\[ \Rightarrow \frac{a}{b} = 2\]

\[ \Rightarrow a = 2b\]

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Introduction of Binomial Theorem
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Chapter 18: Binomial Theorem - Exercise 18.3 [Page 45]

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RD Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.3 | Q 7 | Page 45

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