Question

If α, β are the zeros of kx² – 2x + 3k such that α + β = αβ then k = ?

Options

• `1/3`

• `(-1)/3`

• `2/3`

• `(-2)/3`

Answer 1

`bb(2/3)`

Explanation:

For kx² – 2x + 3k, sum of zeros `α + β = -(-2)/k = 2/k` and product `αβ = (3k)/k = 3 (k ≠ 0)`. 

Given α + β = αβ,

Set `2/k = 3` 

⇒ `k = 2/3`