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If abcdab=cd, show that: acbda3c+ac3b3d+bd3=(a+c)4(b+d)4 - Mathematics

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Question

If `"a"/"b" = "c"/"d"`, show that: `(a^3c + ac^3)/(b^3d + bd^3) = ("a" + "c")^4/("b" + "d")^4`

Sum
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Solution

Let `"a"/"b" = "c"/"d"` = k

⇒ a = bk and c = dk

L.H.S = `("a"^3"c" + "ac"^3)/("b"^3"d" + "bd"^3)`

= `(("bk")^3 xx ("dk")+("bk")("dk"^3))/("b"^3"d"+ "bd"^3)`

= `("b"^3"k"^3"dk"+"bkd"^3"k"^3)/("b"^3"d"+"bd"^3)`

= `("b"^3"dk"^4+"bd"^3"k"^4)/("b"^3"d"+"bd"^3)`

= `("k"^4("b"^3"d"+"bd"^3))/("b"^3"d"+"bd"^3)`

= k4

R.H.S = `("a" + "c")^4/("b" + "d")^4`

= `("bk"+"dk")^4/("b"+"d")^4`

= `("k"^4("b"+"d")^4)/("b"+"d")^4`

= k4

∴ L.H.S = R.H.S

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