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Maharashtra State BoardSSC (English Medium) 10th Standard

If ∆ABC ~ ∆PQR and AB : PQ = 3 : 4 then A(∆ABC) : A(∆PQR) = ?

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Question

If ∆ABC ~ ∆PQR and AB : PQ = 3 : 4 then A(∆ABC) : A(∆PQR) = ?

Options

  • 9 : 25

  • 9 : 16

  • 16 : 9

  • 25 : 9

MCQ
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Solution

9 : 16

Explanation:

In ∆ABC and ∆PQR,

∆ABC ~ ∆PQR

AB : PQ = 3 : 4   ...(Given)

By theorem of areas of similar triangles,

`(A(∆ABC))/(A(∆PQR)) = (AB^2)/(PQ^2)`

`(A(∆ABC))/(A(∆PQR)) = 3^2/4^2`

`(A(∆ABC))/(A(∆PQR)) = 9/16`

∴ A(∆ABC) :  A(∆PQR) = 9 : 16.

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Chapter 1: Similarity - Q.1 (A)
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