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If ∆ABC and ∆DEF are two triangles such that [\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD} = \frac{3}{4}], then write Area (∆ABC) : Area (∆DEF).

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Question

If ∆ABC and ∆DEF are two triangles such that \[\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD} = \frac{3}{4}\], then write Area (∆ABC) : Area (∆DEF).

Sum
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Solution

GIVEN: ΔABC and ΔDEF are two triangles such that.

\[\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD} = \frac{3}{4}\]

TO FIND: Area (ABC) : Area (DEF)

We know that two triangles are similar if their corresponding sides are proportional.

Here, ΔABC and ΔDEF are similar triangles because their corresponding sides are given proportional, i.e. \[\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD} = \frac{3}{4}\]

Since the ratio of the areas of two similar triangle is equal to the ratio of the squares of their corresponding sides.

`⇒ (Area(Δ ABC))/(Area(Δ DEF))=9/12`

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Chapter 7: Triangles - VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) [Page 7.101]

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R.D. Sharma Mathematics [English] Class 10
Chapter 7 Triangles
VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) | Q 13. | Page 7.101
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