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If a1 and a2 are the area of cross-sections of the two conductors of length 'l' each, such that R1 and R2 are their electrical resistance derive a relationship between R1, R2, a1 and a2.

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Question

If a1 and a2 are the area of cross-sections of the two conductors of length 'l' each, such that R1 and R2 are their electrical resistance derive a relationship between R1, R2, a1 and a2.

Long Answer
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Solution

For two conductors made of the same material and having the same length l, resistance is inversely proportional to the area of cross-section:

`R ∝ 1/a`

Using the relation `R = ρl/a`: `R_1 = ρl/a_1` and `R_2 = ρl/a_2`

Dividing the two equations:

`R_1/R_2 = (ρl/a_1)/(ρl/a_2) = a_2/a_1`

Therefore, the required relationship is:

`R_1/R_2 = a_2/a_1`

Equivalently, R1a1 = R2a2.

So, for conductors of equal length made of the same material, their resistances are in the inverse ratio of their areas of cross-section.

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Chapter 7: Electric Circuits, Resistance and Ohm's Law - EXERCISE-1 [Page 149]

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Goyal Brothers Prakashan A New Approach to ICSE Physics [English] Class 10
Chapter 7 Electric Circuits, Resistance and Ohm's Law
EXERCISE-1 | Q 11. (b) | Page 149
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