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Question
If a rod moves a distance \[dx\] in time \[dt\], what is the change in magnetic flux used in the Faraday's Law derivation?
Options
\[d\Phi=B\cdot dx/l\]
\[d\Phi=B\cdot l\cdot dx\]
\[d\Phi=l\cdot dx/B\]
\[d\Phi=B\cdot l\cdot dt\]
MCQ
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Solution
The rod's displacement \[dx\] sweeps out an area \[l\cdot dx\]. Multiplying this area by the magnetic field gives \[d\Phi=B\cdot l\cdot dx\].
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