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If a rod moves a distance \[dx\] in time \[dt\], what is the change in magnetic flux used in the Faraday's Law derivation?

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Question

If a rod moves a distance \[dx\] in time \[dt\], what is the change in magnetic flux used in the Faraday's Law derivation?

Options

  • \[d\Phi=B\cdot dx/l\]

  • \[d\Phi=B\cdot l\cdot dx\]

  • \[d\Phi=l\cdot dx/B\]

  • \[d\Phi=B\cdot l\cdot dt\]

MCQ
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Solution

The rod's displacement \[dx\] sweeps out an area \[l\cdot dx\]. Multiplying this area by the magnetic field gives \[d\Phi=B\cdot l\cdot dx\].

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