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Question
If a letter is choosen randomly from all the letters of the word 'MAINTAINANCE', what is the probability that the choosen letter is a consonant
Sum
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Solution
Total number of letters = 12
Let F represent the case where the chosen letter is a consonant.
Here, consonants are M, N, T, N, N, C.
∴ Number of consonants = 6
Thus, P(E) = `"Number of consonants"/"Total number of letters"`
= `6/12`
= `1/2`
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