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Question
If a chord AB subtends an angle of 60° at the centre of a circle, then the angle between the tangents at A and B is ______.
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Solution
If a chord AB subtends an angle of 60° at the centre of a circle, then the angle between the tangents at A and B is 120°.
Explanation:
Let O be the centre and let the tangents at A and B meet at C.
Since OA ⟂ AC and OB ⟂ BC, in quadrilateral O A C B we have ∠OAC = ∠CB O = 90°.
The interior angles sum to 360°.
So 90° + ∠ACB + 90° + ∠AOB = 360°.
Hence ∠ACB = 180° – ∠AOB
= 180° – 60°
= 120°
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