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Question
If $$a : b = c : d$$, prove that $$(3a + 2b) : (3a - 2b) = (3c + 2d) : (3c - 2d)$$.
Theorem
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Solution
Given: $$a : b = c : d$$
To prove: $$(3a + 2b) : (3a - 2b) = (3c + 2d) : (3c - 2d)$$
Proof:
- $$\frac{a}{b} = \frac{c}{d}$$ [Given]
- $$\frac{3a}{2b} = \frac{3c}{2d}$$ [Multiplying both sides by $$\frac{3}{2}$$]
- $$\frac{3a + 2b}{3a - 2b} = \frac{3c + 2d}{3c - 2d}$$ [By componendo and dividendo]
- $$(3a + 2b) : (3a - 2b) = (3c + 2d) : (3c - 2d)$$
Hence proved.
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