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If A + B = 90°, the value of \frac{\cos A}{\sin B} \times \frac{\tan B}{\cot A} is ______.

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Question

If A + B = 90°, the value of \[\frac{\cos A}{\sin B} \times \frac{\tan B}{\cot A}\] is ______.

Options

  • 1

  • 2

  • sin A

  • cos В

MCQ
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Solution

If A + B = 90°, the value of \[\frac{\cos A}{\sin B} \times \frac{\tan B}{\cot A}\] is 1.

Explanation:

Since A + B = 90°, we have cos A = sin B and tan B = cot A. Substituting these relationships into the expression gives:

\[\frac{\sin B}{\sin B} \times \frac{\cot A}{\cot A} = 1 \times 1 = 1\]
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Chapter 21: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals] - EXERCISE 21 (F) [Page 333]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
EXERCISE 21 (F) | Q 1. (c) | Page 333
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