Advertisements
Advertisements
Question
If \(A\) and \(B\) are invertible matrices of the same order, which expression is the inverse of \(AB\)?
Options
\[(AB)^{-1}=AB\]
\[(AB)^{-1}=BA\]
\[(AB)^{-1}=B^{-1}A^{-1}\]
\[(AB)^{-1}=A^{-1}B^{-1}\]
MCQ
Advertisements
Solution
The inverse of a product is obtained by taking the inverses in reverse order. Hence the inverse of \(AB\) is \(B^{-1}A^{-1}\), not \(A^{-1}B^{-1}\).
shaalaa.com
Is there an error in this question or solution?
