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If A = 1π[sin-1(xπ)tan-1(xπ)sin-1(xπ)cot-1(πx)], B = 1π[-cos-1(xπ)tan-1(xπ)sin-1(xπ)-tan-1(πx)], then A – B is equal to ______. - Mathematics

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Question

If A = `1/pi [(sin^-1(xpi), tan^-1(x/pi)),(sin^-1(x/pi), cot^-1(pix))]`, B = `1/pi [(-cos^-1(x/pi), tan^-1 (x/pi)),(sin^-1(x/pi),-tan^-1(pix))]`, then A – B is equal to ______.

Options

  • I

  • O

  • 2I

  • `1/2"I"`

MCQ
Fill in the Blanks
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Solution

If A = `1/pi [(sin^-1(xpi), tan^-1(x/pi)),(sin^-1(x/pi), cot^-1(pix))]`, B = `1/pi [(-cos^-1(x/pi), tan^-1 (x/pi)),(sin^-1(x/pi),-tan^-1(pix))]`, then A – B is equal to `1/2"I"`.

Explanation:

Given that: A = `1/pi [(sin^-1(xpi), tan^-1(x/pi)),(sin^-1(x/pi), cot^-1(pix))]`

And B = `1/pi [(-cos^-1(x/pi), tan^-1 (x/pi)),(sin^-1(x/pi),-tan^-1(pix))]`

A – B = `1/pi [(sin^-1(xpi), tan^-1(x/pi)),(sin^-1(x/pi), cot^-1(pix))] - 1/pi[(-cos^-1(xpi), tan^-1(x/pi)),(sin^-1(x/pi), -tan^-1(pix))]`

= `1/pi [(sin^-1(xpi) + cos^-1(xpi), tan^-1(x/pi) - tan^-1(x/pi)),(sin^-1(x/pi) -sin^-1(x/pi), cot^-1(pix) + tan^-1(pix))]`

= `1/pi[(pi/2, 0),(0, pi/2)]`  ......`[(because sin^-1x + cos^-1x = pi/2),(tan^-1x + cot^-1x = pi/2)]`

= `1/pi xx pi/2 [(1, 0),(0, 1)]`

= `1/2"I"`

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Chapter 3: Matrices - Exercise [Page 60]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 3 Matrices
Exercise | Q 56 | Page 60

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