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If A(1, 2, 3) and B(4, 5, 6) are two points, then find the foot of the perpendicular from the point B to the line joining the origin and the point A.

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Question

If A(1, 2, 3) and B(4, 5, 6) are two points, then find the foot of the perpendicular from the point B to the line joining the origin and the point A.

Sum
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Solution

Let M be the foot of the perpendicular drawn from B to the line joining O and A.

Let M = (x, y, z)

OM has direction ratios x - 0, y - 0, z - 0 = x, y, z

OA has direction ratios 1 - 0, 2 - 0, 3 - 0 = 1, 2, 3

But O, M, A are collinear.

∴ `"x"/1 = "y"/2 = "z"/3 = "k"`  ....(Let)

∴ x = k, y = 2k, z = 3k

∴  m = (k, 2k, 3k)

BM has direction ratios

k - 4, 2k - 5, 3k - 6

∵ BM is perpendicular to OA.

∴ (1)(k - 4) + 2(2k - 5) + 3(3k - 6) = 0

∴ k - 4 + 4k - 10 + 9k - 18 = 0

∴ 14k = 32

∴ k = `16/7`

∴ M = (k, 2k, 3k) = `(16/7, 32/7, 48/7)`

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Notes

The answer in the textbook is incorrect.

  Is there an error in this question or solution?
Chapter 5: Vectors - Exercise 5.4 [Page 179]
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