Question

If A(1, –1), B(0, 4), C(–5, 3) are vertices of a triangle then find the slope of each side.

Answer 1

A (1, –1), B (0, 4), C (–5, 3) form a triangle. 

\[\text{We know that, slope of line}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]

Slope of AB = \[\frac{4 - \left( - 1 \right)}{0 - 1} = \frac{5}{- 1} = - 5\]

Slope of BC = \[\frac{3 - 4}{- 5 - 0} = \frac{- 1}{- 5} = \frac{1}{5}\]

Slope of AC = \[\frac{3 - \left( - 1 \right)}{- 5 - 1} = \frac{4}{- 6} = \frac{- 2}{3}\]

∴ The slopes of the sides AB, BC and AC are -5, \[\frac{1}{5}\] and \[\frac{-2}3\] respectively.