Advertisements
Advertisements
Question
If (3x − 1)7 = a7x7 + a6x6 + a5x5 +...+ a1x + a0, then a7 + a5 + ...+a1 + a0 =
Options
0
1
128
64
Advertisements
Solution
Given that,
`(3x - 1)^7 = a_7x^2 + a_5x^5 + ...... +a_1x +a_0`
Putting x =1,
We get
`(3 xx1 - 1)^7 = a_6 (1)^5 + a_5 (1)^5 + .......+a_1(1) + a_0`
`a_2 + a_6 + a_5 + ..... +a_1 + a_0 = 128`
APPEARS IN
RELATED QUESTIONS
Write the coefficient of x2 in the following:
`pi/6x^2- 3x+4`
Identify polynomials in the following:
`f(x)=2+3/x+4x`
Identify constant, linear, quadratic and cubic polynomials from the following polynomials:
`r(x)=3x^2+4x^2+5x-7`
If f(x) = 2x2 - 13x2 + 17x + 12 find f(-3).
Find the remainder when x3 + 3x2 + 3x + 1 is divided by 5 + 2x .
x3 + 2x2 − x − 2
x3 − 23x2 + 142x − 120
x3 + 13x2 + 32x + 20
If x + 1 is a factor of x3 + a, then write the value of a.
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
