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Question
If (3x − 1)7 = a7x7 + a6x6 + a5x5 +...+ a1x + a0, then a7 + a5 + ...+a1 + a0 =
Options
0
1
128
64
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Solution
Given that,
`(3x - 1)^7 = a_7x^2 + a_5x^5 + ...... +a_1x +a_0`
Putting x =1,
We get
`(3 xx1 - 1)^7 = a_6 (1)^5 + a_5 (1)^5 + .......+a_1(1) + a_0`
`a_2 + a_6 + a_5 + ..... +a_1 + a_0 = 128`
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