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Question
If –2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1)x + b then
Options
a = –2, b = 6
a = 2, b = –6
a = –2, b = –6
a = 2, b = 6
MCQ
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Solution
a = –2, b = –6
Explanation:
α + β = 3 + (–2)
= 1
And αβ = 3 × (–2)
= –6
∴ –(a + 1) = 1
⇒ a + 1 = –1
⇒ a = –2
Also, b = –6
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