Question

How to connect three resistors each of resistance 8 Ω, so that the equivalent resistance of the combination is 12 Ω? Draw diagram of the combination and justify your answer.

Answer 1

Connect two 8 Ω resistors in parallel.

Then connect this combination in series with the third 8 Ω resistor.

Parallel combination of two 8 Ω:

`1/R_P = 1/8 + 1/8`

= `2/8`

= 4 Ω

Now in series with the third 8 Ω:

R_total = 4 + 8

= 12 Ω