Question

How many terms are there in the series 0.5, 0.53, 0.56, ........, 1.1?

Answer 1

The given series is 0.5, 0.53, 0.56, ........, 1.1

0.53 – 0.5 = 0.03, 0.56 – 0.53 = 0.03, etc.

Thus, the given series is an A.P. with the first term a = 0.5 and common difference d = 0.03

Last term = l = 1.1

0.5 + (n – 1)(0.03) = 1.1

`=>` (n – 1) × 0.03 = 0.6

`=>` n – 1 = 20

`=>` n = 21

Thus, there are 21 terms in the given series.