Advertisements
Advertisements
Question
How many least number of distinct points determine a unique plane?
Advertisements
Solution
If we have two distinct points, then we can draw infinite number of planes passing through those two points. While if we have three distinct non collinear points, only a single unique plane can be drawn passing through those three points.
Therefore, a minimum of three distinct non collinear points are required to get a unique plane.
APPEARS IN
RELATED QUESTIONS
Give a definition of the following term. Are there other terms that need to be defined first? What are they, and how might you define them?
radius of a circle
Consider two ‘postulates’ given below:-
- Given any two distinct points A and B, there exists a third point C which is in between A and B.
- There exist at least three points that are not on the same line.
Do these postulates contain any undefined terms? Are these postulates consistent? Do they follow from Euclid’s postulates? Explain.
The total number of propositions in the Elements are ______.
In Indus Valley Civilisation (about 3000 B.C.), the bricks used for construction work were having dimensions in the ratio ______.
In ancient India, the shapes of altars used for household rituals were ______.
Solve the following question using appropriate Euclid’s axiom:
In the following figure, we have ∠ABC = ∠ACB, ∠3 = ∠4. Show that ∠1 = ∠2.
Solve the following question using appropriate Euclid’s axiom:
In the following figure, we have AC = DC, CB = CE. Show that AB = DE.
Read the following axioms:
- Things which are equal to the same thing are equal to one another.
- If equals are added to equals, the wholes are equal.
- Things which are double of the same thing are equal to one another.
Check whether the given system of axioms is consistent or inconsistent.
The following statement is true or false? Give reason for your answer.
If two circles are equal, then their radii are equal.
The following statement is true or false? Give reason for your answer.
In the following figure, if AB = PQ and PQ = XY, then AB = XY.
