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Question
How many 132 Ω resistors in parallel are required to carry 5 A on a 220 V line?
Numerical
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Solution
Given, V = 220 V, I = 5 A
V = IR
Or R = `"V"/"I"`
In parallel combination, let the no. of resistors be x
`132/x=220/5`
`132/x=44`
x = `132/44`
x = 3
∴ The number of resistors = 3
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2019-2020 (March) Outside Delhi set 3
