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Question
How is the voltage phasor \[V_C\] related in phase to the current?
Options
Voltage leads the current by \[\dfrac{\pi}{2}\] (90°).
Voltage is in phase with the current \[(\phi=0^\circ)\].
Voltage lags the current by \[\dfrac{\pi}{2}\] (90°).
Current lags the voltage \[(\phi<0)\].
MCQ
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Solution
Across a capacitor C, the voltage lags the current by \[\dfrac{\pi}{2}\]. This phase difference is 90°.
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