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Question
How is the magnitude of the electric field \[E\] defined with respect to an equipotential surface?
Options
It equals the change in potential per unit displacement tangential to the equipotential surface at that point.
It equals the change in potential per unit displacement normal to the equipotential surface at that point.
It equals the product of potential and the distance between adjacent surfaces.
It equals the total potential integrated over the entire area of the equipotential surface.
MCQ
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Solution
The magnitude of \[E\] equals the change in potential per unit displacement normal to the equipotential surface at that point, signifying that \[E\] corresponds directly to the potential gradient.
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