Advertisements
Advertisements
Question
How is the following conversion effected propanal into butanone?
Advertisements
Solution
\[\begin{array}{cc}
\phantom{..............................}\ce{OH}\phantom{................................}\ce{O}\phantom{....}\\
\phantom{...........................}|\phantom{...................................}||\phantom{.}\\
\ce{\underset{(Propanal)}{CH3CH2CHO} ->[(i) CH3MgBr][(ii) H^+/H2O] \underset{(Butan-2-ol)}{CH3 - CH2 - CH - CH3} ->[Conc. HNO3][(O)] \underset{(2-Butanone)}{CH3 - CH2 - C - CH3} + H2O}
\end{array}\]
APPEARS IN
RELATED QUESTIONS
Answer in brief.
Observe the following equation of reaction of Tollens' reagent with aldehyde. How do we know that a redox reaction has taken place? Explain.
\[\ce{R-CHO + 2Ag(NH_{3})^{+}_{2} + OH^{-}->[\triangle] R-CO{O}^{-} + 2Ag↓ + 4NH3 + 2H2O}\]
The following compounds will give positive Fehling’s test.
Identify B in the following reaction,
\[\ce{Acetaldoxime ->[Na][alcohol] A ->[NaNO2][HCl] B + H2O + N2\uparrow}\]
Assertion: 2, 2-dimethyl propanoic acid does not give HVZ reaction.
Reason: 2-2, dimethyl propanoic acid does not have α-hydrogen atom.
Identify X and Y.
\[\ce{CH3COCH2CH2COOC2H5 ->[CH3MgBr] X ->[H3O^+] Y}\]
Identify A, B and C.
Which of the following compound will show a positive silver mirror test?
Which of the following is not correctly matched?
Aldehydes are readily oxidised to yield carboxylic acids but ketones are inert to oxidation. Which is the most likely explanation regarding this difference in reactivity?
The products formed in the following reaction, A and B are:
