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Question
How does the electric potential due to a dipole vary with distance compared to that of a point charge?
Options
Dipole potential falls as 1/r², point charge as 1/r
Dipole potential falls as 1/r³, point charge as 1/r²
Both fall off as 1/r
Both fall off as 1/r²
MCQ
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Solution
The electric potential due to a point charge is \[V = \frac{kQ}{r}\], falling as 1/r. For a dipole, the potential is \[V = \frac{p\cos\theta}{4\pi\varepsilon_0 r^2}\], falling as 1/r². This difference arises because a dipole has zero net charge; the potential decays faster with distance than for a net charge.
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