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How does inductive reactance relate voltage amplitude to current amplitude?

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Question

How does inductive reactance relate voltage amplitude to current amplitude?

Options

  • \[i_m=v_mX_L\]

  • \[i_m=\frac{X_L}{v_m}\]

  • \[i_m=\frac{v_m}{X_L}\]

  • \[i_m=v_m+X_L\]

MCQ
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Solution

Since \[X_L=\omega L\], the amplitude relation becomes \[i_m=\frac{v_m}{X_L}\]. This mirrors Ohm's Law, with \[X_L\] playing the role of resistance.

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