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Question
How does inductive reactance relate voltage amplitude to current amplitude?
Options
\[i_m=v_mX_L\]
\[i_m=\frac{X_L}{v_m}\]
\[i_m=\frac{v_m}{X_L}\]
\[i_m=v_m+X_L\]
MCQ
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Solution
Since \[X_L=\omega L\], the amplitude relation becomes \[i_m=\frac{v_m}{X_L}\]. This mirrors Ohm's Law, with \[X_L\] playing the role of resistance.
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